Derivative of sinx=cosx
dy/dx=cosx
y/x=cosx
Here,y=sinx.
sinx/x=cosx
Am I correct?If no,why?

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Solution

Here y=sinx
So that,
dy/dx= d/dx (sinx)=cosx
This is the correct representation.

What you did was, you took dy/dx= y/x ,
which is a wrong representation.
Hope you get it.
Good luck.

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