Question

Derive an expression for the circuit current.

Answer 1

$I_0=\frac{(V_0{)}_R}{R}=\frac{2.5}{300}=8.33\times {10}^{-3}A$
$=8.33mA$
Current function and $V_R$ function are in phase. Hence,
$I=\left(8.33mA\right)\cos \left[\right(950rad/s\left)t\right]$