Derive an expression for the kinetic energy of a body by the calculus method.
as we know,
usingconvservationofenergy
W.D.=ΔKE?
asweknowdw=∫F.dx
=∫ma.dx
=m∫vdvdxdxcos0θ
=m∫vuvdv
=m[v22]vu
=m2(v2−u2)
=ΔKE
ΔKE=12mv2
Derive the expression for kinetic energy.