Derive excess pressure inside a soap bubble expression with charge density p and radius r

Open in App

Solution

Suggest Corrections

Similar questions

Q. A soap bubble of radius 3 cm is charged with surface charge density

σ

such that

\frac{σ^{2}}{ϵ_{0}} = 0.4 S I

units. The excess pressure inside the bubble in SI unit (surface tension of soap solution

= 3 \times 10^{- 3}

N/m) is:

A soap bubble (surface tension T) is charged to a charge density $σ$ . If the pressure inside the bubble is equal to outside pressure in equilibrium, the radius of the bubble is given by

Q. If the excess pressure inside a soap bubble of radius

r_{1}

in air is equal to the excess pressure inside air bubble of radius

r_{2}

inside the soap solution, then

r_{1} : r_{2}

Q. A soap bubble of radius '

r

' is formed in air. The excess pressure inside the bubble is:

Q. A soap bubble of radius

R

is surrounded by another soap bubble of radius

2 R

as shown. Taking surface tension =

S

, the pressure inside the smaller soap bubble, in excess of the atmospheric pressure will be

Join BYJU'S Learning Program