Question

Derive formula of magnetic force between two parallel current carrying wires.

Answer 1

$B_1=\frac{{\mu }_o{i}_1}{2\pi d}$

$F_{21}=i_{2}l{B}_1\sin g{0}^{\circ }=i_{2}l\times \frac{{\mu }_o{i}_1}{2\pi d}$

$\frac{F_{21}}{l}=\frac{{\mu }_o{i}_1{i}_2}{2\pi d}=\frac{F_{12}}{l}=forcepermeterlength$