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Question

Derive the expression for equivalent resistance of series and parallel combination of resistances. Find the ratio of the equivalent resistances of four wires of equal resistances first connected in series then connected in parallel

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Solution

If three resistances are connected in series and current passes through them is I. So this current I will pass through the resistance R1, R2 and R3. Applying Ohms law , it can be found that voltage drops across the resistances will be V1 = IR1, V2 = IR2 and V3= IR3. Now, if total voltage applied across the combination of resistances in series, is V. V = IR1 + IR2+ IR3 .(1)V=IRR=R1+R2+R3When three resistances are connected in parallel. If electric potential difference is applied across this combination, then it will draw a current I (say). As this current will get three parallel paths through these three electrical resistances, the current will be divided into three parts. Say currents I1, I1 and I1 pass through resistor R1, R2and R3 respectively. Where total source current I = I1+ I2 + I3putting, I=V/R1R=1R1+1R2+1R3When 4 resistance are connected in seriesRs=4Rand if connected in parallelRP=R/4RSRp=161

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