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derive the ex...

Question

derive the expression of displacement of a block which is attached to a spring constant k and executing simple harmonic motion

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Solution

$Angular frequency : ω = \sqrt{\frac{k}{m}} Here, k is spring constant and m is mass Displacement : x = A \sin ωt = A sn [(\sqrt{\frac{k}{m}}) t] Here, A is amplitude, k is spring constant, m is mass, and t is time$

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