Derive the formula for the sum of the first n odd positive integer numbers.
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Solution
The sequence of the first n odd positive integer numbers is 1,3,5,7,9,...,2n−1. a1=1,d=2 We know that Sn=a1+a2+a3+....an=n2[2a1+(n−1)d] Sn=2n−12[(2×1+2n−1−1)×2] Sn=2n−12[(2n)×2] Sn=2n(2n−1) Sn=4n2−2n