Application of Negative Numbers in Speed Distance Time
Derive the th...
Question
Derive the third equation of motion graphically.
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Solution
Consider the velocity-time graph of a body moving with uniform acceleration 'a'. Distance travelled in time t, s=(OA+BC)×OC2 =(u+v)×t2 From the first equation of motion, t=(v−u)a Substituting we get, s=(v+u)×(v−u)2a⇒2as=v2−u2