Dertermine the point of the graph of the linear equation 2x+5y=19, whose ordinate is 1x1/2 times the abcissa
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Solution
Given linear equation is 2x + 5y = 19 … (1) Given that ordinate is 1 ½ times its abscissa That is y = 3x /2 Hence equation (1) becomes 2x + 5(3x /2) = 19 19x/2 = 19 Therefore, x = 2 y = 3x/2 = (3 × 2)/2 = 3 Thus the point on the graph is (2, 3).