Describe the experiment simple pendulum to find the value of acceleration due to gravity.

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Solution

Time period of the simple pendulum (measured in seconds.) is given by formula,
$T = 2 π \sqrt{\frac{l}{g}} = \frac{T i m e f o r 30 o c c i l a t i o n s}{30 o s c i l l a t i o n s}$
$⟹ g = 4 π^{2} L / t^{2}$
$S t e r p : 1$ Measure length of pendulum to the middle of pendulum bob.
$S t e p : 2$ Set the pendulum in motion until it completes $30$ to and from oscillations taking care to record this time. Then time period $T$ for one oscillation is is the number recorded divided by $30$ .
$S t e p : 3$ Take total of eight measurements for $g$ $u s i n g t w o d i f f e r e n t m a s s e s . a t$ 4 $d i f f e r e n t v a l u e s f o r t h e l e n g t h$ L$.

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