Describe the motion shown by the following velocity-time graphs.

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Solution

For figure (a)

During interval AB Velocity is +ve, so the particle is moving in +ve direction, but it is slowing down as acceleration (slope of v-7 curve) is negative.
During interval BC Particle remains at rest as the velocity is zero. Acceleration is also zero.
During interval CD Velocity is -ve, so the particle is moving in -ve direction and is speeding up as acceleration is also negative.

For figure (b),

During interval AB Particle is moving in +ve direction with constant velocity and acceleration is zero.
During interval BC Particle is moving in +ve direction as velocity is +ve, but it slows down until it comes to rest as acceleration is negative.
During interval CD Velocity is -ve so the particle is moving in -ve direction and is speeding up as acceleration is also negatived

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During interval AB	Velocity is +ve, so the particle is moving in +ve direction, but it is slowing down as acceleration (slope of v-7 curve) is negative.
During interval BC	Particle remains at rest as the velocity is zero. Acceleration is also zero.
During interval CD	Velocity is -ve, so the particle is moving in -ve direction and is speeding up as acceleration is also negative.

During interval AB	Particle is moving in +ve direction with constant velocity and acceleration is zero.
During interval BC	Particle is moving in +ve direction as velocity is +ve, but it slows down until it comes to rest as acceleration is negative.
During interval CD	Velocity is -ve so the particle is moving in -ve direction and is speeding up as acceleration is also negatived