Describe the nature of image formed when the object is placed at a distance of 20 cm from a concave mirror of focal length 10 cm.

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Solution

Here, u = - 20 cm; f = -10 cm (use Cartesian sign convention)

$1 over v plus 1 over u equals 1 over f fraction numerator begin display style 1 end style over denominator begin display style v end style end fraction plus fraction numerator begin display style 1 end style over denominator begin display style left parenthesis negative 20 right parenthesis end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style left parenthesis negative 10 right parenthesis end style end fraction fraction numerator begin display style 1 end style over denominator begin display style v end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style 20 end style end fraction minus fraction numerator begin display style 1 end style over denominator begin display style 10 end style end fraction space equals space minus 1 over 20 v space equals space minus 20 space c m$
Image is formed at same distance of object. So it is the case of object is placed at Centre of Curvature. So, image is real and inverted.Also have same size as object.

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Describe the nature of image formed when the object is placed at a distance of 20 cm from a concave mirror of focal length 10 cm.

Here, u = - 20 cm; f = -10 cm (use Cartesian sign convention) Image is formed at same distance of object. So it is the case of object is placed at Centre of Curvature. So, image is real and inverted.Also have same size as object.