Describe the shapes of $B F_{3}$ and $B H_{4}^{-}$ . Assign the hybridisation of boron in these species.

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Solution

The central $B$ atom in $B F_{3}$ undergoes $s p^{2}$ hybridization which results in trigonal planar geometry with three bond pairs and 0 lone pairs of electrons.
The central $B$ atom in $B H_{4}^{-}$ undergoes $s p^{3}$ hybridization which results in tetrahedral geometry with 4 bond pairs and 0 lone pairs of electrons.

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B F_{3} - N H_{3}

\begin{matrix} L I S T - I & L I S T - I I (P) P C l_{3} F_{2}, P C l_{2} F_{3} & (1) H y b r i d i s a t i o n o f c e n t r a l a t o m - s a m e, s h a p e o f m o l e c u l e - s a m e, d i p o l e m o m e n t - s a m e (Q) B F_{3}, B C l_{3} & (2) H y b r i d i s a t i o n o f C e n t r a l a t o m - s a m e, s h a p e o f, m o l e c u l e - s a m e, d i p o l e m o m e n t - s a m e i s o e l e c t r o n i c s p e c i e s, u s e d i n f e r t i l i s e r p r e p a r a t i o n (R) C O_{2}, C N_{2}^{- 2} & (3) H y b r i d i s a t i o n o f c e n t r a l a t o m - s a m e, s h a p e o f m o l e c u l e - s a m e, d i p o l e m o m e n t - s a m e, i s o e l e c t r o n i c s p e c i e s, a r o m a t i c (S) C_{6} H_{6}, B_{3} N_{3} H_{6} & (4) H y b r i d i s a t i o n o f c e n t r a l a t o m - s a m e, s h a p e o f m o l e c u l e - s a m e, d i p o l e m o m e n t - d i f f e r e n t \end{matrix}

Question 01

Isostructural species are those which have the same shape and hybridisation. Among the given species identify the isostructural pairs.

(a) $[N F_{3} a n d B F_{3}]$

(b) $[B F_{4}^{-} a n d N H_{4}^{+}]$

(d) $[N H_{3} a n d N O_{3}^{-}]$

N F_{3}, B F_{3}, P F_{5}

[S i F_{6}]^{2 -}

N F_{3}

B F_{3}

P F_{5}

[S i F_{6}]^{2 -}

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