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Question

Describe Van-de-Graaff generator under the following points:
(i) Labelled diagram
(ii) Principle
(iii) Uses (any two)
(iv) Disadvantage.

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Solution

(ii) Principle: We know that the capacity of a uniformly charged hollow spherical conductors is C=4πε0R. Obviously, for the capacity to be large the radius R should be large. Further at the pointed ends of a charged conductor the surface density of charge (i.e., charge/area) is more as compared to any plane surface, therefore the electric field near the pointed ends of conductor is more stronger than at any other places. The working of Van-de Graff generator is based on these facts.
(iii) Uses:
(i) To generate high voltage.
(ii) To accelerate α particles, protons and dentrons etc in nuclear disintegration.
(iv) Disadvantage: Due to its large size it is not convenient to carry it from one place to another.

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