Describe what you would see at anode and cathode during electrolysis of copper (II) chloride, using platinum cathode and carbon anode. Write ionic equations for the reactions at anode and cathode.

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Solution

Electrolysis is the process of breaking the substance into its constituent parts by passing electricity through it when dissolved in water.
The reaction involved is:
Electrolysis of copper (II) chloride :
$C u C l_{2} (a q) \overset{e l e c t r o l y s i s}{\to} C u^{2 +} (a q) + 2 C l^{-} (a q)$
The reaction at the cathode will be:
$C u^{2 +} (a q) + 2 e^{-} \to C u (s)$
The copper will get deposited at the cathode.
The reaction at the anode will be:
$4 O H^{-} (a q) \to O_{2} (g) + 2 H_{2} O (l) + 4 e^{-}$

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