X-4 2x 2x 2x x-4 2x 2x 2x x-4 -5x-44-x2

x+4 amp;2x amp;2x 2x amp;x+4 amp;2x 2x amp;2x amp;x+4 =(x+4)[ x+4 amp;2x; 2x amp;x+4 ] 2x[ 2x amp;2x; 2x am ...

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Definition of a Determinant

x+4 2x 2x ...

Question

$det ∣ ∣ ∣ ∣ \begin{matrix} x + 4 & 2 x & 2 x 2 x & x + 4 & 2 x 2 x & 2 x & x + 4 \end{matrix} ∣ ∣ ∣ ∣$
$= (5 x + 4) (4 - x)^{2}$

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Solution

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Similar questions

∣ ∣ ∣ ∣ \begin{matrix} x + 4 & 2 x & 2 x 2 x & x + 4 & 2 x 2 x & 2 x & x + 4 \end{matrix} ∣ ∣ ∣ ∣ = (5 x + 4) (4 - x)^{2}

∣ ∣ ∣ ∣ \begin{matrix} x + 4 & 2 x & 2 x 2 x & x + 4 & 2 x 2 x & 2 x & x + 4 \end{matrix} ∣ ∣ ∣ ∣ = (5 x + 4) (4 - x)^{2}

∣ ∣ ∣ ∣ \begin{matrix} x + 4 & 2 x & 2 x 2 x & x + 4 & 2 x 2 x & 2 x & x + 4 \end{matrix} ∣ ∣ ∣ ∣ = (5 x + 4) (4 - {x)}^{2}

∣ ∣ ∣ ∣ \begin{matrix} y + k & y & y y & y + k & y y & y & y + k \end{matrix} ∣ ∣ ∣ ∣ = k^{2} (3 y + k)

∣ ∣ ∣ ∣ \begin{matrix} x - 4 & 2 x & 2 x 2 x & x - 4 & 2 x 2 x & 2 x & x - 4 \end{matrix} ∣ ∣ ∣ ∣ = (A + B x) {(x - A)}^{2}

∣ ∣ ∣ ∣ \begin{matrix} x - 4 & 2 x & 2 x 2 x & x - 4 & 2 x 2 x & 2 x & x - 4 \end{matrix} ∣ ∣ ∣ ∣ = (A + B x) (x - A)^{2}

(A, B)

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