Given that,
→A=x1^i+y1^j+z1^k
→B=x2^i+y2^j+z2^k
Now, cross product of →A and →B
→A×→B=(x1^i+y1^j+z1^k)×(x2^i+y2^j+z2^k)
→A×→B=^i(z2y1−y2z1)−^j(z2x1−x2z1)+^k(y2x1−x2y1)
Hence, this is the required solution
If the vectors →a and →b are perpendicular to each other, then a vector →v in terms of →a and →b satisfying the equations →v.→a=0,→v.→b=1 and [→v →a →b]=1 is