Hi,
Let a and d are first term and common difference of an A . P.
nth term = tn = a + ( n - 1 )d----------( 1 )
i) Given t5 = 19
a + 4d = 19 -------(2)
ii ) differnce of the eighth term from
the thirteeth term = 20
t13 - t8 = 20
a + 12d - ( a + 7d ) = 20
a + 12d - a - 7d = 20
5d = 20
d = 4
Put d = 5 in ( 2 )
a + 4d = 19
a + 4 × 4 = 19
a + 16= 19
a = 19 - 16
a =3
Therefore,
a = 3 , d =4
Required A .P is
a , a+ d , a + 2d , a + 3d , .....
3 , 7 , 11 , 15, 19 , ....