Question

Determine an A.P. whose third term is 9 and when fifty term is subtract from $8^{th}$ term, we get 6.

Answer 1

$T_3=+2d=9$

$T_8-T_5=6$

$\Rightarrow a+7d-a-4d=6$

$\Rightarrow 3d=6$

$\Rightarrow d=2$

$a+2\left(2\right)=9$

$\Rightarrow a=5$

$AP=5,7,9,11$….