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Question

Determine ΔH/kJ for the following reaction using the listed enthalpies of reaction:
4CO(g)+8H2(g)3CH4(g)+CO2(g)+2H2O(l)

Given that
C(graphite)+1/2O2(g)CO(g); ΔH/kJ=110.5kJ

CO(g)+1/2O2(g)CO2(g); ΔH/kJ=282.9kJ

H2(g)+1/2O2(g)H2O(l); ΔH/kJ=285.8kJ

C(graphite)+2H2(g)CH4(g); ΔH/kJ=74.8kJ

A
584.9kJmol1
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B
279.8kJmol1
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C
747.4kJmol1
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D
925kJmol1
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Solution

The correct option is C 747.4kJmol1
4CO(g)+8H2(g)3CH4(g)+CO2(g)+2H2O(l); ΔH=?

C(graphite)+1/2O2(g)CO(g); ΔH1=110.5kJ

CO(g)+1/2O2(g)CO2(g); ΔH2=282.9kJ

H2(g)+1/2O2(g)H2O(I); ΔH3=285.8kJ

C(graphite)+2H2(g)CH4(g); ΔH4=74.8kJ

Applying Hess's law,
ΔHr=3×ΔH1+ΔH2+2×ΔH3+3×ΔH4

ΔHr=[3(110.5)282.9+2(285.8)+3(74.8)]
=747.4

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