Determine each of the sums given below using suitable rearrangement.
(i) 953 + 707 + 647
(ii) 1983 + 647 + 217 + 353
(iii) 15409 + 278 + 691 + 422
(iv) 3259 + 10001 + 2641 + 9999
(v) 1 + 2 + 3 + 4 + 96 + 97 + 98 + 99
(vi) 2 + 3 + 4 + 5 + 45 + 46 + 47 + 48

Open in App

Solution

(i) 953 + 707 + 647
953 + (707 + 647) (Using associative property of addition)
= 953 + 1354
= 2307

(ii) 1983 + 647 + 217 + 353
(1983 + 647) + (217 +353) (Using associative property of addition)
= 2630 + 570
= 3200

(iii) 15409 + 278 + 691 + 422
(15409 + 278) + (691 + 422) (Using associative property of addition)
= 15687 + 1113
= 16800

(iv) 3259 + 10001 + 2641 + 9999
(3259 + 10001) + (2641 + 9999) (Using associative property of addition)
= 13260 + 12640
= 25900

(v)1 + 2 + 3 + 4 + 96 + 97 + 98 + 99
(1 + 2 + 3 + 4) + (96 + 97 + 98 + 99) (Using associative property of addition)
= (10) + (390)
= 400

(vi) 2 + 3 + 4 + 5 + 45 + 46 + 47 + 48
(2 + 3 + 4 + 5) + (45 + 46 + 47 + 48) (Using associative property of addition)
= 14 + 186
= 200

Suggest Corrections

Similar questions

40

Weight	$45$	$46$	$47$	$48$	$49$	$50$	$51$	$52$	$53$
Median	$6$	$2$	$3$	$4$	$7$	$4$	$7$	$4$	$3$

Using binomial theorem evaluate each of the following:

$(i) (96)^{3} (i i) (102)^{5} (i i i) (101)^{4} (i v) (98)^{5}$

(\frac{n}{k})

n

k

(\frac{99}{97}) + (\frac{98}{96}) + (\frac{97}{95}) + . . . . . . . . + (\frac{3}{1}) + (\frac{2}{0})

Join BYJU'S Learning Program