Question

Determine equivalent weight of underlined species taking its molecular weight as $M$.

$2H_{2}O\underset{}{\overset{\Delta }{\to }}\underset{–}{2H_2}+\underset{–}{O_2}$

• A. $O_2=\frac{M}{4};H_2=\frac{M}{3}$
• B. $O_4=\frac{M}{3};H_2=\frac{M}{2}$
• C. $O_2=\frac{M}{4};H_2=\frac{M}{2}$
• D. None of these

Answer 1

The correct option is D None of these

$\text{Equivalent Weight}=\frac{\text{Molecular Weight}}{\text{Change in Oxidation State}}$

$\begin{array}{c}\text{Change in}0.5\text{of Hydrogen}=|1-0|=1\\ \text{Change in}0.5\text{of}{O}_{\text{xygen}}=|0-(-2)|=2\\ Eq\cdot {\text{wt of}}^{\prime }{H}_2^{\prime }=M\text{, Equivalent of}{O}_2=\frac{M}{2}\end{array}$