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Standard XII

Chemistry

Le Chatelier's Principle for Del N Equals to 0

Determine fin...

Question

Determine final pressure after the value is left opened for a long time in the apparatus represented in figure. Assume that the temperature is fixed at $300 K$ . Under the given conditions assume no reaction of $C O$ & $O_{2}$ .

1.59

atm

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3.284

atm

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6.568

atm

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None of these

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Solution

The correct option is B $3.284$ atm
The number of moles of $C O$ $= \frac{P V}{R T} = \frac{2.463 \times 2}{0.0821 \times 300} = 0.2$

The number of moles of $O_{2} = \frac{P V}{R T} = \frac{4.926 \times 1}{0.0821 \times 300} = 0.2$

Total number of moles $= 0.2 + 0.2 = 0.4$
Total volume $= 2 + 1 = 3$

Final pressure $= \frac{n R T}{V} = \frac{0.4 \times 0.0821 \times 300}{3} = 3.284 a t m$

Hence, the correct option is $B$

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Determine final pressure after the value is left opened for a long time in the apparatus represented in figure. Assume that the temperature is fixed at 300 K. Under the given conditions assume no reaction of CO & O2.

The correct option is B 3.284 atmThe number of moles of CO =PVRT=2.463×20.0821×300=0.2The number of moles of O2=PVRT=4.926×10.0821×300=0.2Total number of moles =0.2+0.2=0.4Total volume =2+1=3Final pressure =nRTV=0.4×0.0821×3003=3.284atmHence, the correct option is B

Determine final pressure after the value is left opened for a long time in the apparatus represented in figure. Assume that the temperature is fixed at $300 K$ . Under the given conditions assume no reaction of $C O$ & $O_{2}$ .