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Question

Determine graphically the vertices of the triangle, the equations of whose side are give below:
y=x,y=0 and 3x+3y=10

A
(0,0)(103,0)(53,53)
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B
(0,0)(173,0)(53,53)
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C
(0,0)(143,0)(53,53)
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D
(0,0)(103,0)(53,83)
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Solution

The correct option is A (0,0)(103,0)(53,53)
As shown in the graph , to find vertices of required triangle,
We can find intersection of lines
1. 3x+3y=10 and y=x which is (53,53)
2. y=0 and 3x+3y=10 which is (103,0)
3. y=x and y=0 which is origin (0,0)

1394214_986202_ans_d0d152ea8f0a4aec8c7a3906bcf6d2f0.png

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