Question

Determine gravitational attraction between two asteroids separated by $22000$$\text{m}$ if their masses are $450000$$\text{kg}$ and $700000\text{kg}$ respectively.

• A. $1.2\times {10}^{-6}$N
• B. $1.2\times {10}^{-8}$N
• C. $4.3\times {10}^{-8}$N
• D. $2.8\times {10}^{-6}$N

Answer 1

The correct option is C

$4.3\times {10}^{-8}$N

Given:

Distance of separation of two asteroids $=22000\text{m}$

Mass of first asteroid $=M_1=450000\text{kg}$

Mass of second asteroid $=M_2=700000\text{kg}$

To Find: Gravitational force

Solution:

We have,

$$\begin{gathered} F=G{M}_1{M}_2/r^2 \\ \text{where,} \\ {M}_1=450000kg \\ {M}_{2=}700000kg \\ G=6.67\times {10}^{-11} \\ r=22000m \\ \text{So}, \\ F=\frac{(6.67\times {10}^{-11}\times 450000\times 700000)}{{\left(22000\right)}^2} \\ F=4.3\times {10}^{-8}N \end{gathered}$$

Hence, the correct option is (c).