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Byju's Answer
Standard XII
Mathematics
Property 4
Determine int...
Question
Determine interval of 'a' for which the graph of quadratic expression
x
2
+
(
a
−
1
)
x
+
16
always lie above x-axis for all real
x
.
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Solution
To lie above x-axis, descriminant must be less than 0
⇒
(
a
−
1
)
2
−
4.16
<
0
⇒
(
a
−
1
+
64
)
(
a
−
1
−
64
)
<
0
⇒
(
a
+
63
)
(
a
−
65
)
<
0
⇒
a
∈
(
−
63
,
65
)
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Similar questions
Q.
Determine interval of 'a' for which the graph of the quadratic expression
x
2
+
(
a
−
1
)
x
+
16
always lie above x-axis for all real
x
.
Q.
For quadratic expression
y
=
a
x
2
+
b
x
+
c
,
a
>
0.
It's graph will always lie above the vertex.
Q.
(a) Let
y
=
√
(
(
x
+
1
)
(
x
−
3
)
x
−
2
)
.
Find all the real values of x for which y takes real values.
(b) Determine all real values of x for which the expression
{
2
x
2
−
x
+
1
−
1
x
+
1
−
2
x
+
1
x
1
+
1
}
1
/
2
takes real values.
Q.
Find all possible values of 'a' for which exactly one root of the quadratic equation
x
2
−
(
a
+
1
)
x
+
2
a
=
0
lie in the interval
(
0
,
3
)
Q.
Assertion :Statement-1:
c
o
t
−
1
(
x
)
−
t
a
n
−
1
(
x
)
>
0
for all
x
<
1
Reason: Statement-2: Graph of
c
o
t
−
1
(
x
)
is always above the graph of
t
a
n
−
1
(
x
)
for all
x
<
1
.
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