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Question

Determine Kc for 2SO2(g)+O2(g)2SO3(g),Kp=3.4 bar1 at 1000oC:

A
159
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B
259
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C
359
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D
459
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Solution

The correct option is C 359

Given reaction scheme

2SO2(g)+O2(g)2SO3(g)

ng= nproducts-nreactants =2(2+1)=23=1

Formula: Kp=Kc(RT)Δn

Kp is equilibrium constant from partial pressures = 3.4 bar-1

Kc is the equilibrium constant from concentrations =?

R is gas constant = 0.08314 L bar-1 K-1 mol-1

T is temperature = 1000oC = 1000+273 = 1273K

On substituting we get

Kc=3.4bar1(0.08314LbarK1mol1×1273K)1

Kc=3.4×0.08314×1273Lmol1=359Lmol1

Hence opt. C is correct.

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