Determine Kc for 2SO2(g)+O2(g)⇌2SO3(g),Kp=3.4 bar−1 at 1000oC:
Given reaction scheme
2SO2(g)+O2(g)⇌2SO3(g)
∆ng= nproducts-nreactants =2−(2+1)=2−3=−1
Formula: Kp=Kc(RT)Δn
Kp is equilibrium constant from partial pressures = 3.4 bar-1
Kc is the equilibrium constant from concentrations =?
R is gas constant = 0.08314 L bar-1 K-1 mol-1
T is temperature = 1000oC = 1000+273 = 1273K
On substituting we get
Kc=3.4bar−1(0.08314LbarK−1mol−1×1273K)−1
Kc=3.4×0.08314×1273Lmol−1=359Lmol−1
Hence opt. C is correct.