Determine k so that 2+3,k,5+8k are three consecutive terms in AP.

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Solution

Dear student,
Assuming the question to be 2+3k, k, 5+8k
a1=2+3k
a2=k
a3=5+8k
So, a2-a1=a3-a2
k-(2+3k)=5+8k-(k)
k-2-3k= 5+8k-k
-2k-2=5+7k
9k=-7
k=(-7/9)
Regards

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