Question

Determine $k$, so that $\frac{2}{3},k$ and $\frac{5}{8}$ are the three consecutive terms of an $A.P.$

Answer 1

We have,

$\frac{2}{3},k,\frac{5}{8}$ are in A.P.

So,

$2k=\frac{2}{3}+\frac{5}{8}$

$2k=\frac{16+15}{24}$

$k=\frac{31}{48}$

Hence, this is the answer.