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Question

Determine n if, 2nC3:nC3=12:1

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Solution

Determine n, if 2nC3:nC3=12:1
2nC3=12nC3
2n!2n3!3!=12n!n3!3!
2n(2n1)(2n2)2n3!2n3!3×2=122(n)(n1)(n2)n3!n3!×3×2
n(2n1)(n1)3=2(n)(n1)(n2)
2n1=3n6
tn=t5
n=5

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