Determine order and degree (when defined) of differential equations.
${(\frac{d s}{d t})}^{4} + 3 s \frac{d^{2} s}{d t^{2}} = 0.$

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Solution

The highest order derivative present in the given differential equation is $d^{2} s / d t^{2} .$ Therefore, the index of its highest power is one, hence the given differential equation is of order 2 and degree 1.

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