Determine order and degree (when defined) of differential equations.
$y^{''} + (y^{'})^{2} + 2 y = 0.$

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Solution

The highest order derivative, present in the given differential equation is y''. Therefore, its order is two. The given differential equation is a polynomial equation in y'' and y' and the highest power raised to y''is 1. Hence its degree is 1.

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