CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Determine P(EF)
Mother, father and son line up at random for a family picture

Open in App
Solution

If mother (m) , father (i) and son (s) line for the family picture, then the sample space will be S = {mfs, msf, fms, fsm, smf, sfm}
n(S)=6 Which contains 6 equally likely sample events.
here, E = set of events having son on one end and
F= set of event having father in the middle
E=mfs,fms,smf,sfm,F=mfs,sfm and EF=mfs,sfmn(E)=4,n(F)=2,m)EF)=2 .Now,P(E)=Number of favourable outcomesTotal number of outcomes=46=23
Similarly, P(F)=26=13andP(EF)=26=13
We know that P (EF)=P(EF)P(F)=1313=1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Probability Distribution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon