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Question

Determine the angular separation between central maximum and first order maximum of the diffraction pattern due to a single slit of width 0.25 mm when light of wavelength 5890A0 is incident on it normally?

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Solution

asinθ=(2n+1)λ2=(2×1+1)λ2=3λ2
when θ s small, sinθ=θ

aθ=3λ2
θ3λ2a=3×5890×10102×0.25×103
=3.534×103rad
Total angular spread=±3.534×103rad

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