Question

Determine the bar force in the member DE

• A. 67.66 kN
• B. 66.67 kN
• C. 100 kN
• D. 50 kN

Answer 1

The correct option is B 66.67 kN

Due to symmetry of loading
$R_A=R_B=100kN$

Taking moment at joint 'L'


$F_{DE}\times 6+100\times 4=0$

$F_{DE}=\frac{-400}{6}=-66.67kN\left(compression\right)$