wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Determine the charge on the capacitor in the following circuit

A
110 μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
60 μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200 μC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2 μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 200 μC

In steady state capacitor behaves as open circuit
The circuit can be reduced as following:

Hence, Req=9 Ω
Given E=72 V
The current supplied by the battery

i=72 V9 Ω=8 A. (ohm's law )

Thus, the current supplied by the battery is 8 A.

assume zero potential at lower potential terminal of cell
Now distributing currents using KCL and writing potentials at different nodes using ohms law .

ohm's law for 6Ω:
VAVBR=8A

72VVB6Ω=8A

VB=24V

ohm's law for 2Ω:
VBVCR=2A

24VVC2Ω=2A

VC=20 V

We can observe the potential difference across the capacitor is 20V.

Now, voltage across capacitor ,
V=20V,

C=10μF

charge on capacitor q=CV

=10×106F×20V=200 μC

Hence, option C is correct.


flag
Suggest Corrections
thumbs-up
36
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon