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Question

Determine the current through the battery in the circuit shown in figure. After a long time:

213478_e8e7898ffe294bec8a406db2cd915ee1.png

A
ER2+R3
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B
2ER1+R3
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C
E2R1+R3
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D
ER1+R3
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Solution

The correct option is C ER1+R3
After long time switch S is closed, the both capacitors C1,C2 are fully charged and no current will pass through them. So the current I drawn from the battery will flow only the resistances R1,R3.
Thus, I=E/(R1+R2)

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