Question

Determine the electric potential at the surface of the gold nucleus. The radius is $6.6\times {10}^{-5}m$ and the atomic number $Z=79$ . Given charge on a proton $=1.6\times {10}^{-19}C.$

Answer 1

The electric potential at the surface of the gold nucleus is given as

$V=\frac{Ze}{4\pi {\epsilon }_{0}r}$

By substituting the values in the above equation we get

$V=\frac{9\times {10}^9\times 79\times 1.6\times {10}^{-19}}{6.6\times {10}^{-5}}$

$V=172.3\times {10}^{-5}$

Hence, the electric potential is $172.3\times {10}^{-5}$