Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen. [H = 1, N = 14, O = 16].

NOH₃

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NOH₂

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NOH₄

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NOH₆

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NOH

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Solution

The correct option is A
NOH₃

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Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen. [N = 14, O = 16, H = 1]

Q. A compound has the following percentage composition by mass:
Carbon - 54.55%, Hydrogen - 9.09% and Oxygen - 36.26%. Its vapour density is 44. Find the Empirical and Molecular formula of the compound. (H = 1; C = 12; O = 16).

Q. A compound gave the following data of its composition by mass: C=57.82 %, O=38.58 % and the rest hydrogen. Its vapour density is 83. Empirical formula of compound is:

(C=12, O=16, H=1)

The percentage composition of sodium phosphate, as determined by analysis is: 42.1% of sodium, 18.9% of phosphorus and 39% of oxygen. Find the empirical formula of the compound (work to two decimal places). [H = 1, N = 14, O = 16, Na = 23, P = 31, Cl = 35.5, Pt = 195]

(a) Calculate the percentage of boron (B) in borax (Na₂B₄O₇·10H₂O). (H = 1, B = 11, O = 16, Na = 23).
(b) (i) The compound A has the following percentage composition by mass:
Carbon = 26.7%, oxygen = 71.1%, hydrogen = 2.2%. Determine the empirical formula of A (H = 1, C = 12, O = 16)
(ii) If the relative molecular mass of A is 90, what is the molecular formula of A?

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Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen. [H = 1, N = 14, O = 16].

The correct option is A NOH3

The correct option is A
NOH₃