1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Determine the equation of the plane on which the co - ordinates of the foot of perpendicular drawn from origin O is the point P(α,β,γ).

A
α2x+β2y+γ2z=α3+β3+γ3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
αx+βy+γz=α2+β2+γ2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
α2x+β2y+γ2z=α+β+γ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B αx+βy+γz=α2+β2+γ2Given that OP is normal to planeSo the Drs of normal to the plane is α,β,γTherefore the equation of plane is αx+βy+γz=kThe point (α,β,γ) lies on the planeSo we have α2+β2+γ2=kTherefore the equation of plane is αx+βy+γz=α2+β2+γ2Therefore the correct option is B

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program