Determine the equilibrium constant of the following reaction at 298 K- 2Fe3- - Sn2- 2Fe2- - Sn4-Given- E-Sn4- Sn2- - 0-15 volt- E-Fe3- Fe2- - 0-771 volt-

Calculate E^∘_cell . The value of 0.0621 volt .Apply E^∘_cell = 0.05912log K K = 1.0× 10^21 . ...

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Equilibrium Constant from Nernst Equation

Determine the...

Question

Determine the equilibrium constant of the following reaction at $298 K$ :
$2 F e^{3 +} + S n^{2 +} \to 2 F e^{2 +} + S n^{4 +}$
(Given: $E_{S n^{4 +} / S n^{2 +}}^{\circ} = 0.15 v o l t; E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.771 v o l t$ ).

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F e^{3 +}

F e^{2 +} / P t

S n^{4 +}

S n^{2 +} / P t

+ 0.77 V

0.15 V

25^{o} C

S n^{4 +} + 2 F e^{2 +} \to S n^{2 +} + 2 F e^{3 +}

S n C l_{2}

F e C l_{3}

2 F e^{3 +} + S n^{2 +} \to 2 F e^{2 +} + S n^{4 +}

K C N S

F e^{3 +}

2 F e^{3 +} (a q) + S n^{2 +} (a q) \to 2 F e^{2 +} (a q) + A

E_{F e^{3 +} / F e^{2 +}}^{\circ} = + 0.77 V; E_{S n^{2 +} / S n}^{\circ} = - 0.14 V

S n_{(s)} + 2 F e_{(a q)}^{3 +} \to 2 F e_{(a q)}^{2 +} + S n_{(a q)}^{2 +}

K_{c}

C u^{2 +} (a q) + S n^{2 +} (a q) ⟶ S n^{4 +} (a q) + C u (s)

25^{\circ} C

E_{C u^{2 +} | C u}^{\circ} = 0.34 V; E_{S n^{4 +} | S n^{2 +}}^{\circ} = 0.15 V

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