Determine the general term of an A.P. whose 7th term is −1 and 16th term 17.
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Solution
Let a be the first term and d be the common difference of the given A.P. Let the A.P. be a1,a2,a3,...,an,...
It is given that a7=−1 and a16=17
⟹a+(7−1)d=−1 and a+(16−1)d=17
⟹a+6d=−1 ...(i)
and, a+15d=17 ...(ii) Subtracting equation (i) from equation (ii), we get 9d=18⟹d=2 Putting d=2 in equation (i), we get a+12=−1⟹a=13 Hence, General term =an=a+(n−1)d=−13+(n−1)×2=2n−15