Checking commutative.
Given : a∗b=1∀a,b∈R
∗ is commutative if
a∗b=b∗a
Now,
a∗b=1
And,
b∗a=1
Since
a∗b=b∗a ∀a,b∈R
∗ is commutative.
Checking associative
∗ is associative if
(a∗b)∗c=a∗(b∗c)
Now,
(a∗b)∗c=1∗c
=1
a∗(b∗c)=a∗1
=1
Since (a∗b)∗c=a∗(b∗c)∀a,b,c,∈R
∗ is an associative binary operation.