Determine the line containing the point (2,3)

$2 x + 3 y = 5$

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$3 x - 2 y = 0$

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$2 x + 3 y = 12$

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$4 x - 3 y = 1$

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Solution

The correct option is B
$3 x - 2 y = 0$

If a point lies on straight line represented by a equation, then it satisfies the equation.

Substitute the point (2,3) in each equation.

$3 x - 2 y = 0$

$L H S = 3 (2) - 2 (3)$

$L H S = 6 - 6 = 0$

$\Rightarrow L H S = R H S$

$\Rightarrow$ Point (2,3)lies on the equation $3 x - 2 y = 0$

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