Determine the mass in grams of 1 mole of KAl(SO4)2⋅12H2O?
A
132
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B
180
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C
394
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D
474
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E
516
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Solution
The correct option is C474 The mass in grams of 1 mole of KAl(SO4)2⋅12H2O is equal to its molar mass. It is 39+27+2(32+4(16))+12(2+16)=66+2(96)+12(18)=66+192+216=474g