Question

Determine the missing parts of triangle $ABC$ from the given information.
$A={35}^o,B={25}^o,c=67.6$

Answer 1

Given, $A=35$ , $B=25$ , $c=67.6$

$\Rightarrow C=120$
By sine rule, we get

$\frac{c}{\sin C}=\frac{a}{\sin A}=\frac{b}{\sin B}$
We get $a=67.6\times \frac{\left(\sin 35\right)}{\left(\sin 120\right)}=44.77$
$\Rightarrow b=67.6\times \frac{\sin \left(25\right)}{\sin \left(120\right)}=32.98$