Question

Determine the molarity of solution obtained by mixing $50ml$ of $0.26M{H}_{2}S{O}_4$ solution with another $150ml$ of $0.48M{H}_{2}S{O}_4$ solution?

• A. $0.500M$
• B. $0.740M$
• C. $0.425M$
• D. $0.625M$

Answer 1

The correct option is C $0.425M$

Total moles of $H_{2}S{O}_4=(50\times 0.26+150\times 0.48)\times {10}^{-3}=85\times {10}^{-3}$

Total volume $=150+50=200mL$

$\therefore$ Molarity after mixing $=\frac{85\times {10}^{-3}}{200\times {10}^{-3}}=0.425M$