Question

Determine the moles of potassium ions present in 2.50 L of 0.200 M potassium sulfate?

• A. 0.0800 mol
• B. 0.160 mol
• C. 0.400 mol
• D. 0.500 mol
• E. 1.00 mol

Answer 1

Answer: (E)

1.00 mol

The formula of potassium sulfate = $K_{2}S{O}_4$
$Molarity\times Volume=Moles=0.2\times 2.5=0.5moles$
1 mol of $K_{2}S{O}_4$ $\equiv$ 2 moles of $K^{+}$ ions.
0.5 moles of $K_{2}S{O}_4$ $\equiv$ 1 moles of $K^{+}$ ions.