Given: y2 – 5y + 11 = 0
To find the nature of the roots, we need to find the discriminant of the given quadratic equation.
We know that the discriminant of a quadratic equation is Δ =b2 – 4ac.
On comparing the given equation with ay2 + by + c = 0 in variable y, we get:
a = 1, b = –5 and c = 11
Thus,
Δ = (–5)2 – 4(1)(11)
=> Δ = 25 – 44 = –19
Since Δ < 0, the roots of the given quadratic equation are not real.